25p^2+30p+8=0

Solution for 25p^2+30p+8=0 equation:

25p^2+30p+8=0

a = 25; b = 30; c = +8;
Δ = b2-4ac
Δ = 302-4·25·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*25}=\frac{-40}{50}
=-4/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*25}=\frac{-20}{50}
=-2/5
$